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(2x+6)(2x+7)=156
We move all terms to the left:
(2x+6)(2x+7)-(156)=0
We multiply parentheses ..
(+4x^2+14x+12x+42)-156=0
We get rid of parentheses
4x^2+14x+12x+42-156=0
We add all the numbers together, and all the variables
4x^2+26x-114=0
a = 4; b = 26; c = -114;
Δ = b2-4ac
Δ = 262-4·4·(-114)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-50}{2*4}=\frac{-76}{8} =-9+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+50}{2*4}=\frac{24}{8} =3 $
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