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(2x+55)=(x+35)
We move all terms to the left:
(2x+55)-((x+35))=0
We get rid of parentheses
2x-((x+35))+55=0
We calculate terms in parentheses: -((x+35)), so:We get rid of parentheses
(x+35)
We get rid of parentheses
x+35
Back to the equation:
-(x+35)
2x-x-35+55=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20
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