(2x+5)=4-(3+x)

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Solution for (2x+5)=4-(3+x) equation: 



(2x+5)=4-(3+x)

We move all terms to the left:

(2x+5)-(4-(3+x))=0

We add all the numbers together, and all the variables

(2x+5)-(4-(x+3))=0

We get rid of parentheses

2x-(4-(x+3))+5=0



We calculate terms in parentheses: -(4-(x+3)), so:

4-(x+3)

determiningTheFunctionDomain
-(x+3)+4

We get rid of parentheses

-x-3+4

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We get rid of parentheses

2x+1x-1+5=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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