(2x+5)=(8x-181/2)

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Solution for (2x+5)=(8x-181/2) equation: 



(2x+5)=(8x-181/2)

We move all terms to the left:

(2x+5)-((8x-181/2))=0

We add all the numbers together, and all the variables

(2x+5)-((+8x-181/2))=0

We get rid of parentheses

2x-((+8x-181/2))+5=0

We multiply all the terms by the denominator


2x*2))-((+8x-181+5*2))=0

We add all the numbers together, and all the variables

2x*2))-((8x-171))=0

We add all the numbers together, and all the variables

2x*2))-((8x=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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