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(2x+5)/3=x+1
We move all terms to the left:
(2x+5)/3-(x+1)=0
We get rid of parentheses
(2x+5)/3-x-1=0
We multiply all the terms by the denominator
(2x+5)-x*3-1*3=0
We add all the numbers together, and all the variables
(2x+5)-x*3-3=0
Wy multiply elements
(2x+5)-3x-3=0
We get rid of parentheses
2x-3x+5-3=0
We add all the numbers together, and all the variables
-1x+2=0
We move all terms containing x to the left, all other terms to the right
-x=-2
x=-2/-1
x=+2
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