(2x+5)/3+(4x+9)/6+(3-4x)/2=20

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Solution for (2x+5)/3+(4x+9)/6+(3-4x)/2=20 equation: 



(2x+5)/3+(4x+9)/6+(3-4x)/2=20

We move all terms to the left:

(2x+5)/3+(4x+9)/6+(3-4x)/2-(20)=0

We add all the numbers together, and all the variables

(2x+5)/3+(4x+9)/6+(-4x+3)/2-20=0

We calculate fractions

There is no solution for this equation

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