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(2x+5)/(x+4)=1
We move all terms to the left:
(2x+5)/(x+4)-(1)=0
Domain of the equation: (x+4)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-4
x∈R
(2x+5)-1*(x+4)=0
We get rid of parentheses
2x-1*(x+4)+5=0
We move all terms containing x to the left, all other terms to the right
2x-1*(x+4)=-5
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