(2x+5)+(x-3)+(3x+1)=39

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Solution for (2x+5)+(x-3)+(3x+1)=39 equation: 



(2x+5)+(x-3)+(3x+1)=39

We move all terms to the left:

(2x+5)+(x-3)+(3x+1)-(39)=0

We get rid of parentheses

2x+x+3x+5-3+1-39=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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