(2x+5)+(3x+16)=9x-19

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Solution for (2x+5)+(3x+16)=9x-19 equation: 



(2x+5)+(3x+16)=9x-19

We move all terms to the left:

(2x+5)+(3x+16)-(9x-19)=0

We get rid of parentheses

2x+3x-9x+5+16+19=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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