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(2x+5)(x-5)=35
We move all terms to the left:
(2x+5)(x-5)-(35)=0
We multiply parentheses ..
(+2x^2-10x+5x-25)-35=0
We get rid of parentheses
2x^2-10x+5x-25-35=0
We add all the numbers together, and all the variables
2x^2-5x-60=0
a = 2; b = -5; c = -60;
Δ = b2-4ac
Δ = -52-4·2·(-60)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{505}}{2*2}=\frac{5-\sqrt{505}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{505}}{2*2}=\frac{5+\sqrt{505}}{4} $
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