(2x+5)(x-3)/x+3=7

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Solution for (2x+5)(x-3)/x+3=7 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((2*x+5)*(x-3))/x+3 = 7 // - 7

((2*x+5)*(x-3))/x-7+3 = 0

((2*x+5)*(x-3))/x+(-7*x)/x+(3*x)/x = 0

(2*x+5)*(x-3)-7*x+3*x = 0

2*x^2-8*x+3*x-15 = 0

2*x^2-5*x-15 = 0

2*x^2-5*x-15 = 0

2*x^2-5*x-15 = 0

DELTA = (-5)^2-(-15*2*4)

DELTA = 145

DELTA > 0

x = (145^(1/2)+5)/(2*2) or x = (5-145^(1/2))/(2*2)

x = (145^(1/2)+5)/4 or x = (5-145^(1/2))/4

(x-((5-145^(1/2))/4))*(x-((145^(1/2)+5)/4)) = 0

((x-((5-145^(1/2))/4))*(x-((145^(1/2)+5)/4)))/x = 0

((x-((5-145^(1/2))/4))*(x-((145^(1/2)+5)/4)))/x = 0 // * x

(x-((5-145^(1/2))/4))*(x-((145^(1/2)+5)/4)) = 0

( x-((145^(1/2)+5)/4) )

x-((145^(1/2)+5)/4) = 0 // + (145^(1/2)+5)/4

x = (145^(1/2)+5)/4

( x-((5-145^(1/2))/4) )

x-((5-145^(1/2))/4) = 0 // + (5-145^(1/2))/4

x = (5-145^(1/2))/4

x in { (145^(1/2)+5)/4, (5-145^(1/2))/4 }

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