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(2x+5)(x+3)=2x^2+11x+15
We move all terms to the left:
(2x+5)(x+3)-(2x^2+11x+15)=0
We get rid of parentheses
-2x^2+(2x+5)(x+3)-11x-15=0
We multiply parentheses ..
-2x^2+(+2x^2+6x+5x+15)-11x-15=0
We get rid of parentheses
-2x^2+2x^2+6x+5x-11x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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