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(2x+5)(5x-4)=180
We move all terms to the left:
(2x+5)(5x-4)-(180)=0
We multiply parentheses ..
(+10x^2-8x+25x-20)-180=0
We get rid of parentheses
10x^2-8x+25x-20-180=0
We add all the numbers together, and all the variables
10x^2+17x-200=0
a = 10; b = 17; c = -200;
Δ = b2-4ac
Δ = 172-4·10·(-200)
Δ = 8289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8289}=\sqrt{9*921}=\sqrt{9}*\sqrt{921}=3\sqrt{921}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-3\sqrt{921}}{2*10}=\frac{-17-3\sqrt{921}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+3\sqrt{921}}{2*10}=\frac{-17+3\sqrt{921}}{20} $
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