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(2x+5)(5-7x)=0
We add all the numbers together, and all the variables
(2x+5)(-7x+5)=0
We multiply parentheses ..
(-14x^2+10x-35x+25)=0
We get rid of parentheses
-14x^2+10x-35x+25=0
We add all the numbers together, and all the variables
-14x^2-25x+25=0
a = -14; b = -25; c = +25;
Δ = b2-4ac
Δ = -252-4·(-14)·25
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-45}{2*-14}=\frac{-20}{-28} =5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+45}{2*-14}=\frac{70}{-28} =-2+1/2 $
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