(2x+4x)2-18+(10x/2x)

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Solution for (2x+4x)2-18+(10x/2x) equation: 


x in (-oo:+oo)

(2*x+4*x)^2+((10*x)/2)*x-18 = 0

36*x^2+5*x^2-18 = 0

36*x^2+5*x^2-18 = 0

41*x^2-18 = 0

41*x^2-18 = 0

41*x^2 = 18 // : 41

x^2 = 18/41

x^2 = 18/41 // ^ 1/2

abs(x) = (18/41)^(1/2)

x = (18/41)^(1/2) or x = -(18/41)^(1/2)

x in { (18/41)^(1/2), -(18/41)^(1/2) }

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