(2x+40)5x=360

Solution for (2x+40)5x=360 equation:

(2x+40)5x=360

We move all terms to the left:

(2x+40)5x-(360)=0

We multiply parentheses

10x^2+200x-360=0

a = 10; b = 200; c = -360;
Δ = b2-4ac
Δ = 2002-4·10·(-360)
Δ = 54400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54400}=\sqrt{1600*34}=\sqrt{1600}*\sqrt{34}=40\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-40\sqrt{34}}{2*10}=\frac{-200-40\sqrt{34}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+40\sqrt{34}}{2*10}=\frac{-200+40\sqrt{34}}{20}
$