(2x+40)+(3x-50)=15002

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Solution for (2x+40)+(3x-50)=15002 equation: 



(2x+40)+(3x-50)=15002

We move all terms to the left:

(2x+40)+(3x-50)-(15002)=0

We get rid of parentheses

2x+3x+40-50-15002=0

We add all the numbers together, and all the variables

5x-15012=0

We move all terms containing x to the left, all other terms to the right

5x=15012

x=15012/5

x=3002+2/5

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