(2x+4/x)=(x-8/3)

Solution for (2x+4/x)=(x-8/3) equation:

(2x+4/x)=(x-8/3)

We move all terms to the left:

(2x+4/x)-((x-8/3))=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2x+4/x)-((+x-8/3))=0

We get rid of parentheses

2x+4/x-((+x-8/3))=0

We calculate fractions


2x+()/3x^2+(-((+x-8*x)/3x^2=0

We add all the numbers together, and all the variables

2x+()/3x^2+(-((-7x)/3x^2=0

We multiply all the terms by the denominator


2x*3x^2+(-((-7x)+()=0


We calculate terms in parentheses: +(-((-7x)+(), so:

-((-7x)+(


Wy multiply elements

6x^3+(-((-7x)+()=0


We calculate terms in parentheses: +(-((-7x)+(), so:

-((-7x)+(


We do not support expression: x^3