(2x+4)/6=(x+2)/3

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Solution for (2x+4)/6=(x+2)/3 equation: 



(2x+4)/6=(x+2)/3

We move all terms to the left:

(2x+4)/6-((x+2)/3)=0

We calculate fractions


2x/()+(-((x+2)*6)/()=0



We calculate terms in parentheses: +(-((x+2)*6)/(), so:

-((x+2)*6)/(

We multiply all the terms by the denominator


-((x+2)*6)



We calculate terms in parentheses: -((x+2)*6), so:

(x+2)*6

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

-6x-12

Back to the equation:

+(-6x-12)



We get rid of parentheses

2x/()-6x-12=0

We multiply all the terms by the denominator


2x-6x*()-12*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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