(2x+4)/5=(3x-3)/3

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Solution for (2x+4)/5=(3x-3)/3 equation: 



(2x+4)/5=(3x-3)/3

We move all terms to the left:

(2x+4)/5-((3x-3)/3)=0

We calculate fractions


2x/()+(-((3x-3)*5)/()=0



We calculate terms in parentheses: +(-((3x-3)*5)/(), so:

-((3x-3)*5)/(

We multiply all the terms by the denominator


-((3x-3)*5)



We calculate terms in parentheses: -((3x-3)*5), so:

(3x-3)*5

We multiply parentheses

15x-15

Back to the equation:

-(15x-15)



We get rid of parentheses

-15x+15

Back to the equation:

+(-15x+15)



We get rid of parentheses

2x/()-15x+15=0

We multiply all the terms by the denominator


2x-15x*()+15*()=0

We add all the numbers together, and all the variables

2x-15x*()=0

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