(2x+4)+20=(5x+15)

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Solution for (2x+4)+20=(5x+15) equation: 



(2x+4)+20=(5x+15)

We move all terms to the left:

(2x+4)+20-((5x+15))=0

We get rid of parentheses

2x-((5x+15))+4+20=0



We calculate terms in parentheses: -((5x+15)), so:

(5x+15)

We get rid of parentheses

5x+15

Back to the equation:

-(5x+15)



We add all the numbers together, and all the variables

2x-(5x+15)+24=0

We get rid of parentheses

2x-5x-15+24=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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