(2x+4)+(3x+6)=48

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Solution for (2x+4)+(3x+6)=48 equation: 



(2x+4)+(3x+6)=48

We move all terms to the left:

(2x+4)+(3x+6)-(48)=0

We get rid of parentheses

2x+3x+4+6-48=0

We add all the numbers together, and all the variables

5x-38=0

We move all terms containing x to the left, all other terms to the right

5x=38

x=38/5

x=7+3/5

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