(2x+4)(2x-4)=8

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Solution for (2x+4)(2x-4)=8 equation:


Simplifying
(2x + 4)(2x + -4) = 8

Reorder the terms:
(4 + 2x)(2x + -4) = 8

Reorder the terms:
(4 + 2x)(-4 + 2x) = 8

Multiply (4 + 2x) * (-4 + 2x)
(4(-4 + 2x) + 2x * (-4 + 2x)) = 8
((-4 * 4 + 2x * 4) + 2x * (-4 + 2x)) = 8
((-16 + 8x) + 2x * (-4 + 2x)) = 8
(-16 + 8x + (-4 * 2x + 2x * 2x)) = 8
(-16 + 8x + (-8x + 4x2)) = 8

Combine like terms: 8x + -8x = 0
(-16 + 0 + 4x2) = 8
(-16 + 4x2) = 8

Solving
-16 + 4x2 = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4x2 = 8 + 16

Combine like terms: -16 + 16 = 0
0 + 4x2 = 8 + 16
4x2 = 8 + 16

Combine like terms: 8 + 16 = 24
4x2 = 24

Divide each side by '4'.
x2 = 6

Simplifying
x2 = 6

Take the square root of each side:
x = {-2.449489743, 2.449489743}

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