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(2x+4)(2x+3)=56
We move all terms to the left:
(2x+4)(2x+3)-(56)=0
We multiply parentheses ..
(+4x^2+6x+8x+12)-56=0
We get rid of parentheses
4x^2+6x+8x+12-56=0
We add all the numbers together, and all the variables
4x^2+14x-44=0
a = 4; b = 14; c = -44;
Δ = b2-4ac
Δ = 142-4·4·(-44)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-30}{2*4}=\frac{-44}{8} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+30}{2*4}=\frac{16}{8} =2 $
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