(2x+36)(x+18)=0

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Solution for (2x+36)(x+18)=0 equation: 



(2x+36)(x+18)=0

We multiply parentheses ..

(+2x^2+36x+36x+648)=0

We get rid of parentheses

2x^2+36x+36x+648=0

We add all the numbers together, and all the variables

2x^2+72x+648=0

a = 2; b = 72; c = +648;
Δ = b2-4ac
Δ = 722-4·2·648
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-72}{4}=-18$

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