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(2x+350)(2x+200)=74.464
We move all terms to the left:
(2x+350)(2x+200)-(74.464)=0
We add all the numbers together, and all the variables
(2x+350)(2x+200)-74.464=0
We multiply parentheses ..
(+4x^2+400x+700x+70000)-74.464=0
We get rid of parentheses
4x^2+400x+700x+70000-74.464=0
We add all the numbers together, and all the variables
4x^2+1100x+69925.536=0
a = 4; b = 1100; c = +69925.536;
Δ = b2-4ac
Δ = 11002-4·4·69925.536
Δ = 91191.424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1100)-\sqrt{91191.424}}{2*4}=\frac{-1100-\sqrt{91191.424}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1100)+\sqrt{91191.424}}{2*4}=\frac{-1100+\sqrt{91191.424}}{8} $
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