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(2x+30)(2x+30)+x+50=180
We move all terms to the left:
(2x+30)(2x+30)+x+50-(180)=0
We add all the numbers together, and all the variables
x+(2x+30)(2x+30)-130=0
We multiply parentheses ..
(+4x^2+60x+60x+900)+x-130=0
We get rid of parentheses
4x^2+60x+60x+x+900-130=0
We add all the numbers together, and all the variables
4x^2+121x+770=0
a = 4; b = 121; c = +770;
Δ = b2-4ac
Δ = 1212-4·4·770
Δ = 2321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(121)-\sqrt{2321}}{2*4}=\frac{-121-\sqrt{2321}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(121)+\sqrt{2321}}{2*4}=\frac{-121+\sqrt{2321}}{8} $
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