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(2x+30)(2x+25)=2(30)(25)
We move all terms to the left:
(2x+30)(2x+25)-(2(30)(25))=0
determiningTheFunctionDomain (2x+30)(2x+25)-23025=0
We multiply parentheses ..
(+4x^2+50x+60x+750)-23025=0
We get rid of parentheses
4x^2+50x+60x+750-23025=0
We add all the numbers together, and all the variables
4x^2+110x-22275=0
a = 4; b = 110; c = -22275;
Δ = b2-4ac
Δ = 1102-4·4·(-22275)
Δ = 368500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{368500}=\sqrt{100*3685}=\sqrt{100}*\sqrt{3685}=10\sqrt{3685}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-10\sqrt{3685}}{2*4}=\frac{-110-10\sqrt{3685}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+10\sqrt{3685}}{2*4}=\frac{-110+10\sqrt{3685}}{8} $
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