(2x+3)=(7x+5)

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Solution for (2x+3)=(7x+5) equation: 



(2x+3)=(7x+5)

We move all terms to the left:

(2x+3)-((7x+5))=0

We get rid of parentheses

2x-((7x+5))+3=0



We calculate terms in parentheses: -((7x+5)), so:

(7x+5)

We get rid of parentheses

7x+5

Back to the equation:

-(7x+5)



We get rid of parentheses

2x-7x-5+3=0

We add all the numbers together, and all the variables

-5x-2=0

We move all terms containing x to the left, all other terms to the right

-5x=2

x=2/-5

x=-2/5

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