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(2x+3)6=96
We move all terms to the left:
(2x+3)6-(96)=0
We multiply parentheses
12x+18-96=0
We add all the numbers together, and all the variables
12x-78=0
We move all terms containing x to the left, all other terms to the right
12x=78
x=78/12
x=6+1/2
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