(2x+3)/5=(x-4)/2

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Solution for (2x+3)/5=(x-4)/2 equation: 


x in (-oo:+oo)

(2*x+3)/5 = (x-4)/2 // - (x-4)/2

(2*x+3)/5-((x-4)/2) = 0

(2*x+3)/5+(-1*(x-4))/2 = 0

(2*(2*x+3))/(2*5)+(-1*5*(x-4))/(2*5) = 0

2*(2*x+3)-1*5*(x-4) = 0

26-x = 0

(26-x)/(2*5) = 0

(26-x)/(2*5) = 0 // * 2*5

26-x = 0

26-x = 0 // - 26

-x = -26 // * -1

x = 26

x = 26

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