(2x+3)/4=(4x-2)/6

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Solution for (2x+3)/4=(4x-2)/6 equation: 



(2x+3)/4=(4x-2)/6

We move all terms to the left:

(2x+3)/4-((4x-2)/6)=0

We calculate fractions


2x/()+(-((4x-2)*4)/()=0



We calculate terms in parentheses: +(-((4x-2)*4)/(), so:

-((4x-2)*4)/(

We multiply all the terms by the denominator


-((4x-2)*4)



We calculate terms in parentheses: -((4x-2)*4), so:

(4x-2)*4

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

-16x+8

Back to the equation:

+(-16x+8)



We get rid of parentheses

2x/()-16x+8=0

We multiply all the terms by the denominator


2x-16x*()+8*()=0

We add all the numbers together, and all the variables

2x-16x*()=0

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