(2x+3)/3x-6-(x+1)/2x-4=(3x-5)/4x-8

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Solution for (2x+3)/3x-6-(x+1)/2x-4=(3x-5)/4x-8 equation:


x in (-oo:+oo)

x*((2*x+3)/3)-(x*((x+1)/2))-6-4 = x*((3*x-5)/4)-8 // - x*((3*x-5)/4)-8

x*((2*x+3)/3)-(x*((x+1)/2))-(x*((3*x-5)/4))-6-4+8 = 0

(x*(2*x+3))/3+(-1*x*(x+1))/2+(-1*x*(3*x-5))/4-6-4+8 = 0

(2*4*x*(2*x+3))/(2*3*4)+(-1*3*4*x*(x+1))/(2*3*4)+(-1*2*3*x*(3*x-5))/(2*3*4)+(-6*2*3*4)/(2*3*4)+(-4*2*3*4)/(2*3*4)+(2*3*4*8)/(2*3*4) = 0

2*4*x*(2*x+3)-1*3*4*x*(x+1)-1*2*3*x*(3*x-5)-6*2*3*4-4*2*3*4+2*3*4*8 = 0

4*x^2-18*x^2+12*x+30*x-144-96+192 = 0

42*x-14*x^2-144-96+192 = 0

42*x-14*x^2-240+192 = 0

42*x-14*x^2-48 = 0

42*x-14*x^2-48 = 0

2*(21*x-7*x^2-24) = 0

21*x-7*x^2-24 = 0

DELTA = 21^2-(-24*(-7)*4)

DELTA = -231

DELTA < 0

2 = 0

2/(2*3*4) = 0

2/(2*3*4) = 0 // * 2*3*4

2 = 0

x belongs to the empty set

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