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(2x+3)/3+2x=10
We move all terms to the left:
(2x+3)/3+2x-(10)=0
We add all the numbers together, and all the variables
2x+(2x+3)/3-10=0
We multiply all the terms by the denominator
2x*3+(2x+3)-10*3=0
We add all the numbers together, and all the variables
2x*3+(2x+3)-30=0
Wy multiply elements
6x+(2x+3)-30=0
We get rid of parentheses
6x+2x+3-30=0
We add all the numbers together, and all the variables
8x-27=0
We move all terms containing x to the left, all other terms to the right
8x=27
x=27/8
x=3+3/8
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