(2x+3)/(2x+6)=7/3

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Solution for (2x+3)/(2x+6)=7/3 equation: 



(2x+3)/(2x+6)=7/3

We move all terms to the left:

(2x+3)/(2x+6)-(7/3)=0



Domain of the equation: (2x+6)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-6

x!=-6/2

x!=-3

x∈R



We add all the numbers together, and all the variables

(2x+3)/(2x+6)-(+7/3)=0

We get rid of parentheses

(2x+3)/(2x+6)-7/3=0

We calculate fractions


(6x+9)/(6x+18)+(-14x-42)/(6x+18)=0

We multiply all the terms by the denominator


(6x+9)+(-14x-42)=0

We get rid of parentheses

6x-14x+9-42=0

We add all the numbers together, and all the variables

-8x-33=0

We move all terms containing x to the left, all other terms to the right

-8x=33

x=33/-8

x=-4+1/8

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