If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x+3)+1/2(x+3)=49
We move all terms to the left:
(2x+3)+1/2(x+3)-(49)=0
Domain of the equation: 2(x+3)!=0We get rid of parentheses
x∈R
2x+1/2(x+3)+3-49=0
We multiply all the terms by the denominator
2x*2(x+3)+3*2(x+3)-49*2(x+3)+1=0
Wy multiply elements
4x^2(x+6x(x-98x(x+1=0
| 3D+10d-11=17 | | 10.5x2/3= | | (2x+78)=5x | | 7(x+4)=-140 | | 5-m=7+2m-4 | | x÷25=13 | | 5(7.4a+2)=65 | | 3(2x-1)+7=46 | | 4(p+4)=-4 | | 1.5x+1.6(12-x)=18.5 | | 3s-2s+4=9 | | 2(x+3)-2=49=7x | | 4(p+4)=–4 | | 13/3=u/5 | | 19.15+x(0.07)=23 | | -7=h-21 | | 125m-100m+43,560=43,900-200m | | 7(4+d)=-42 | | -1x3x-13-25=0 | | -(-11x+4)=40 | | z+27°z–18°z–39=180 | | 7d=–6+6d | | -(5x-13)=78 | | 2(5x+3)^4/3+1=33 | | 2y-14+16y=4 | | k-1+k=-9 | | h13=–24 | | 9x×1=91 | | 1.5.x=21 | | 17=2n−13+8n | | 20=12v-7v | | 15g+13g=14 |