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(2x+3)+(x+3)+x=74
We move all terms to the left:
(2x+3)+(x+3)+x-(74)=0
We add all the numbers together, and all the variables
x+(2x+3)+(x+3)-74=0
We get rid of parentheses
x+2x+x+3+3-74=0
We add all the numbers together, and all the variables
4x-68=0
We move all terms containing x to the left, all other terms to the right
4x=68
x=68/4
x=17
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