(2x+3)+(6x-5)=22

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Solution for (2x+3)+(6x-5)=22 equation: 



(2x+3)+(6x-5)=22

We move all terms to the left:

(2x+3)+(6x-5)-(22)=0

We get rid of parentheses

2x+6x+3-5-22=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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