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(2x+3)(3x+2)=(3x+4)(2x-1)
We move all terms to the left:
(2x+3)(3x+2)-((3x+4)(2x-1))=0
We multiply parentheses ..
(+6x^2+4x+9x+6)-((3x+4)(2x-1))=0
We calculate terms in parentheses: -((3x+4)(2x-1)), so:We get rid of parentheses
(3x+4)(2x-1)
We multiply parentheses ..
(+6x^2-3x+8x-4)
We get rid of parentheses
6x^2-3x+8x-4
We add all the numbers together, and all the variables
6x^2+5x-4
Back to the equation:
-(6x^2+5x-4)
6x^2-6x^2+4x+9x-5x+6+4=0
We add all the numbers together, and all the variables
8x+10=0
We move all terms containing x to the left, all other terms to the right
8x=-10
x=-10/8
x=-1+1/4
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