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(2x+3)(3x+11)=0
We multiply parentheses ..
(+6x^2+22x+9x+33)=0
We get rid of parentheses
6x^2+22x+9x+33=0
We add all the numbers together, and all the variables
6x^2+31x+33=0
a = 6; b = 31; c = +33;
Δ = b2-4ac
Δ = 312-4·6·33
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-13}{2*6}=\frac{-44}{12} =-3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+13}{2*6}=\frac{-18}{12} =-1+1/2 $
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