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(2x+3)(3x+1)=-3
We move all terms to the left:
(2x+3)(3x+1)-(-3)=0
We add all the numbers together, and all the variables
(2x+3)(3x+1)+3=0
We multiply parentheses ..
(+6x^2+2x+9x+3)+3=0
We get rid of parentheses
6x^2+2x+9x+3+3=0
We add all the numbers together, and all the variables
6x^2+11x+6=0
a = 6; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·6·6
Δ = -23
Delta is less than zero, so there is no solution for the equation
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