(2x+2x)=(12+15)+(7x-1)

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Solution for (2x+2x)=(12+15)+(7x-1) equation: 



(2x+2x)=(12+15)+(7x-1)

We move all terms to the left:

(2x+2x)-((12+15)+(7x-1))=0

We add all the numbers together, and all the variables

(+4x)-(27+(7x-1))=0

We get rid of parentheses

4x-(27+(7x-1))=0



We calculate terms in parentheses: -(27+(7x-1)), so:

27+(7x-1)

determiningTheFunctionDomain
(7x-1)+27

We get rid of parentheses

7x-1+27

We add all the numbers together, and all the variables

7x+26

Back to the equation:

-(7x+26)



We get rid of parentheses

4x-7x-26=0

We add all the numbers together, and all the variables

-3x-26=0

We move all terms containing x to the left, all other terms to the right

-3x=26

x=26/-3

x=-8+2/3

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