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(2x+25)(2x+20)=500
We move all terms to the left:
(2x+25)(2x+20)-(500)=0
We multiply parentheses ..
(+4x^2+40x+50x+500)-500=0
We get rid of parentheses
4x^2+40x+50x+500-500=0
We add all the numbers together, and all the variables
4x^2+90x=0
a = 4; b = 90; c = 0;
Δ = b2-4ac
Δ = 902-4·4·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90}{2*4}=\frac{-180}{8} =-22+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90}{2*4}=\frac{0}{8} =0 $
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