(2x+23)x=95

Solution for (2x+23)x=95 equation:

(2x+23)x=95

We move all terms to the left:

(2x+23)x-(95)=0

We multiply parentheses

2x^2+23x-95=0

a = 2; b = 23; c = -95;
Δ = b2-4ac
Δ = 232-4·2·(-95)
Δ = 1289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1289}}{2*2}=\frac{-23-\sqrt{1289}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1289}}{2*2}=\frac{-23+\sqrt{1289}}{4}
$