(2x+20)+(5x-11)=(11x-63)

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Solution for (2x+20)+(5x-11)=(11x-63) equation: 



(2x+20)+(5x-11)=(11x-63)

We move all terms to the left:

(2x+20)+(5x-11)-((11x-63))=0

We get rid of parentheses

2x+5x-((11x-63))+20-11=0



We calculate terms in parentheses: -((11x-63)), so:

(11x-63)

We get rid of parentheses

11x-63

Back to the equation:

-(11x-63)



We add all the numbers together, and all the variables

7x-(11x-63)+9=0

We get rid of parentheses

7x-11x+63+9=0

We add all the numbers together, and all the variables

-4x+72=0

We move all terms containing x to the left, all other terms to the right

-4x=-72

x=-72/-4

x=+18

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