(2x+20)+(5x-11)+(180-(11x-63))=180

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Solution for (2x+20)+(5x-11)+(180-(11x-63))=180 equation: 



(2x+20)+(5x-11)+(180-(11x-63))=180

We move all terms to the left:

(2x+20)+(5x-11)+(180-(11x-63))-(180)=0

We get rid of parentheses

2x+5x+(180-(11x-63))+20-11-180=0



We calculate terms in parentheses: +(180-(11x-63)), so:

180-(11x-63)

determiningTheFunctionDomain
-(11x-63)+180

We get rid of parentheses

-11x+63+180

We add all the numbers together, and all the variables

-11x+243

Back to the equation:

+(-11x+243)



We add all the numbers together, and all the variables

7x+(-11x+243)-171=0

We get rid of parentheses

7x-11x+243-171=0

We add all the numbers together, and all the variables

-4x+72=0

We move all terms containing x to the left, all other terms to the right

-4x=-72

x=-72/-4

x=+18

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