(2x+20)+(4x-30)+(3x-5)=180

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Solution for (2x+20)+(4x-30)+(3x-5)=180 equation: 



(2x+20)+(4x-30)+(3x-5)=180

We move all terms to the left:

(2x+20)+(4x-30)+(3x-5)-(180)=0

We get rid of parentheses

2x+4x+3x+20-30-5-180=0

We add all the numbers together, and all the variables

9x-195=0

We move all terms containing x to the left, all other terms to the right

9x=195

x=195/9

x=21+2/3

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