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(2x+20)(2x+40)=16641064
We move all terms to the left:
(2x+20)(2x+40)-(16641064)=0
We multiply parentheses ..
(+4x^2+80x+40x+800)-16641064=0
We get rid of parentheses
4x^2+80x+40x+800-16641064=0
We add all the numbers together, and all the variables
4x^2+120x-16640264=0
a = 4; b = 120; c = -16640264;
Δ = b2-4ac
Δ = 1202-4·4·(-16640264)
Δ = 266258624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{266258624}=\sqrt{64*4160291}=\sqrt{64}*\sqrt{4160291}=8\sqrt{4160291}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-8\sqrt{4160291}}{2*4}=\frac{-120-8\sqrt{4160291}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+8\sqrt{4160291}}{2*4}=\frac{-120+8\sqrt{4160291}}{8} $
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