(2x+2)=(3x-5)+5x-5

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Solution for (2x+2)=(3x-5)+5x-5 equation: 



(2x+2)=(3x-5)+5x-5

We move all terms to the left:

(2x+2)-((3x-5)+5x-5)=0

We get rid of parentheses

2x-((3x-5)+5x-5)+2=0



We calculate terms in parentheses: -((3x-5)+5x-5), so:

(3x-5)+5x-5

We add all the numbers together, and all the variables

5x+(3x-5)-5

We get rid of parentheses

5x+3x-5-5

We add all the numbers together, and all the variables

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

2x-8x+10+2=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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