(2x+2)(x+3)=160

Solution for (2x+2)(x+3)=160 equation:

(2x+2)(x+3)=160

We move all terms to the left:

(2x+2)(x+3)-(160)=0

We multiply parentheses ..

(+2x^2+6x+2x+6)-160=0

We get rid of parentheses

2x^2+6x+2x+6-160=0

We add all the numbers together, and all the variables

2x^2+8x-154=0

a = 2; b = 8; c = -154;
Δ = b2-4ac
Δ = 82-4·2·(-154)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-36}{2*2}=\frac{-44}{4}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+36}{2*2}=\frac{28}{4}
=7
$